Age Problem Questions – Practice Set 01 for Govt & Academic Exams

Introduction to Problems on Ages In almost every competitive exam like SSC, Banking, Railway, or State-level PSC exams, one common topic in the Quantitative Aptitude section is "Problems on Ages". These questions test your ability to form and solve equations based on age-related conditions.This Set 01 contains selected Problems on Ages with clear solutions, ideal for both beginners and advanced learners preparing for govt job exams or academic assessments.

Start solving this Age Problem Questions – Set 01 to master age-related questions for competitive and academic exams. Includes solved examples, tricks, and key formulas.

Key Concepts Used in Age Problem Questions:

Concept	Description
Present Age	The age of the person as of now
Future Age	Age after ‘x’ years = Present Age + x
Past Age	Age ‘x’ years ago = Present Age – x
Equation Formation	Use given conditions to form equations and solve

📝 Age Problem Questions – Practice Set 01:

Q1. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7 : 9, find the age of Sachin.
a) 26.5
b) 25.5
c) 24.5
d) 23.5

Correct Option is: c) 24.5
Explanation: Let Sachin = 7x, Rahul = 9x
Rahul – Sachin = 7
=> 9x – 7x = 7
=> 2x = 7
⇒ x = 3.5
Sachin’s age = 7x = 7 × 3.5 = 24.5 years.
Method 2: Difference of ratio= 9-7=2 units
2 units => 7 years
1 units => 3.5 years
Therefore, Age of Sachin= 7 units= 7 × 3.5 = 24.5 years.

Q2. Tanya’s grandfather was 8 times older than her 16 years ago. He would be 3 times her age 8 years from now. What was the ratio of the ages of Tanya and her grandfather 8 years ago?
A. 10 : 20
B. 11 : 51
C. 11 : 53
D. 12 : 51

Correct Option is: C. 11 : 53
Explanation: Let Tanya’s age now = x; grandfather = y
16 years ago: y-16 = 8(x-16)
After 8 years: y+8 = 3(x+8)
Solving:
From (2): y+8 = 3x+24 ⇒ y = 3x+16
From (1): y-16 = 8x-128 ⇒ y = 8x-112
Equate:
8x-112 = 3x+16
5x = 128 ⇒ x = 25.6
y = 3(25.6)+16 = 76.8 + 16 = 91.8
8 years ago:
Tanya = 25.6 – 8 = 17.6
Grandfather = 91.8 – 8 = 83.8
Ratio = 17.6 : 83.8 = 11:53

Q3. The average age of a man and his son is 48 years. The ratio of their ages is 11 : 5. What will be the ratio of their ages after 6 years?
A. 6 : 5
B. 2 : 1
C. 2 : 3
D. 3 : 1

Correct Option is: B. 2 : 1
Explanation: Sum = 48 × 2 = 96
Let ages be 11x & 5x
⇒ 11x+5x=96
⇒ x=6
So ages: Man=66, Son=30
After 6 years: 72 & 36
⇒ Ratio: 72:36 = 2:1
Method 2: Given ratio=11:5
Average= (11+5)/2= 8 units.
8 units ⇒ 48 years
1 units ⇒ 6 years
Man’s present age = 11*6 =66 years
And, Son’s present age = 5*6= 30 years.
Man’s & Son’s ages after 6 years are 72 years & 36 years respectively.
Therefore, Ratio of Man: Son will be = 72:36=2:1

Q4. The ratio between the school ages of Neeta and Samir is 5 : 6 respectively. If the ratio between one-third age of Neeta and half of Samir’s age is 5 : 9, then what is the school age of Samir?
A. 20 years
B. 25 years
C. 30 years
D. Can’t be determined

Correct Option is: D. Can’t be determined
Explanation: Let Neeta = 5x, Samir = 6x
(5x)/3 : (6x)/2 = 5:9
(5x/3):(3x) = 5:9
Cross-multiplied:
(5x/3) × 9 = 5×3x
15x = 15x (Holds for any x)
So, Can’t be determined

Q5. Sushil was thrice as old as Snehal 6 years back. Sushil will be twice as old as Snehal 6 years hence. How old is Snehal today?
A. 12
B. 14
C. 16
D. 18

Correct Option is: D. 18
Explanation: Let, Snehal’s age 6 years back was =x
So, Sushil’s age was 3x
Sushil’s age after 6 years from present= 3x+12
Snehal’s age after 6 years from present= x+12
So, (3x+12)/( x+12)=2:1
⇒ 3x+12= 2x+24
⇒ x= 12
Therefor, Snehal’s age today is (x+6) years= 12+6=18 years.

Q6. The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of his son. After 6 years, the sum of the ages of father and his son will be:
A. 72 years
B. 73 years
C. 74 years
D. 75 years

Correct Option is: A. 72 years
Explanation: Let present father = x, son = 60–x
6 yrs ago: x–6 = 5[(60–x)–6]
x–6 = 5(54–x)
x–6 = 270–5x
x+5x = 270+6
6x = 276 ⇒ x=46
Son = 14
After 6 years, Father = 52, Son = 20
Sum = 72

Q7. The present age of a father is 3 years more than three times the age of his son. Three years hence, father’s age will be 10 years more than twice the age of his son. The father’s present age is:
A. 33 years
B. 39 years
C. 45 years
D. 40 years

Correct Option is: A. 33 years
Explanation: Let son = x; Father = 3x+3
After 3: Father = (3x+3)+3 = 3x+6
Son = x+3
Given: 3x+6 = 2(x+3)+10
⇒ 3x+6 = 2x+6+10
3x+6 = 2x+16
⇒ x = 10
Father = 3×10+3=33

Q8. My grandmother was 9 times older than me 16 years ago. He would be 3 times my age, 8 years from now. Eight years ago what was the ratio of my age to that of my grandmother?
A. 3 : 8
B. 1 : 5
C. 1 : 2
D. None of these

Correct Option is: B. 1 : 5
Explanation: Let current ages: you = x, grandma = y
16 yrs ago: y-16 = 9(x-16)
After 8: y+8 = 3(x+8)
From (2): y+8 = 3x+24
⇒ y = 3x+16
From (1): y-16 = 9x-144
⇒ y = 9x-128
Equate: 3x+16 = 9x-128 ⇒ 6x=144⇒ x=24
y=3×24+16=88
8 yrs ago: you: 24-8=16; grandma: 88-8=80
⇒ 16:80=1:5

Q9. When the average age of a husband, wife, and their son was 42 years, the son got married and a child was born just one year after the marriage. When the child turned five years old, the average age of the family became 36 years. What was the age of daughter-in-law at the time of marriage?
A. 26 years
B. 25 years
C. 24 years
D. 23 years

Correct Option is: B. 25 years
Explanation: Let S’s age at marriage = x
After 1 year, kid born:
Now, kid = 5
⇒ marriage was 6 yrs ago
6 yrs back sum ages = 3 × 42 = 126
Now, this family is 5 members (son, wife, kid, parents), avg: 36 × 5 = 180
Increase in sum = 180 – 126 = 54
Sum of increases = 6 yrs for each old (4 people) + 5 yrs for kid + age of daughter-in-law at marriage
(4 × 6) + 5 + W = 24 + 5 + W = 29 + W = 54
⇒ W = 25

Q10. The present average age of a family of four members is 36 years. If the present age of the youngest member of the family is 12 years, what was the average age of the family at the birth of the youngest member?
A. 48 years
B. 40 years
C. 32 years
D. 24 years

Correct Option is: C. 32 years
Explanation: Now: 4 × 36 = 144
At youngest’s birth, total age = (each member 12 years younger, youngest is newborn = 0):
So, sum = 144 – (4×12) + 12 = 144 – 48 = 96 (since youngest was not born yet, only 3 members)
Avg = 96 ÷ 3 = 32

🎯 Why Practice Age Problem Questions Regularly?

They improve your logical thinking and equation solving speed.
Very commonly asked in govt job exams, so repeated practice is essential.
Helps in improving algebraic equation handling for academic exams as well.

📌 Tips to Solve Age Problem Questions Quickly:

Use variables smartly (Let present age = x).
Translate words into math equations.
Be careful with time reference (present, past, future).
Practice sets like this regularly to boost speed and accuracy.

📚 Related Practice Sets Of Age Problem Questions:

✅ Conclusion

“Age Problem Questions” are an important part of quantitative aptitude sections across government job exams and academic tests. Mastering this topic can give you a significant edge in your preparation. Keep practicing regularly with our curated sets like this Set 01 and move on to the next level confidently.