This blog post brings you Time and Work Questions with Solutions PDF – Practice Set 01, a comprehensive list of 10 hand-picked questions asked in previous SSC exams. Each question includes multiple-choice options (A, B, C, D), correct answers, and step-by-step solutions to help you grasp the logic and approach.
You can also download the time and work questions with solutions PDF at the end for offline practice.
Q1) A can do a piece of work in 20 days, and B can do the same work in 30 days. How many days will they take to complete the work together?
A) 10 days
B) 12 days
C) 15 days
D) 18 days
Correct Option is: B) 12 days
Explanation:
Method 1: A’s 1 day work = 1/20
B’s 1 day work = 1/30
Together = 1/20 + 1/30 = (3 + 2)/60 = 5/60 = 1/12
So, they will finish the work in 12 days.
Smart Method: A does in 20 days & B does in 30 days
Take LCM ( 20,30)= 60 units ( Total Work)
A’s one day’s work= 60/20= 3 units
B’s one day’s work = 60/ 30= 2 units
(A+B)’s one day’s work= 3+2=5 units
So, A & B together will take = 60/5= 12 days to complete the work.
Q2) A is twice as efficient as B. Together they can finish a work in 12 days. In how many days can A alone finish the work?
A) 16 days
B) 18 days
C) 20 days
D) 24 days
Correct Option is: B) 18 days
Explanation:
Method 1: Let B’s work rate be x, so A’s = 2x
Together: x + 2x = 3x
3x × 12 = 36 units of work
A alone does 2x = 2 units/day
Time = 36 / 2 = 18 days
Smart Method: A’s efficiency = 2 unit/day & B’s efficiency= 1 unit/day
Together they complete ( 2+1)= 3 unit work/day
Since, they completes the work together in 12 days,
So, Total work = 12*3 = 36 units.
Now, To complete this 36 units work A alone will take = 36/ 2 =18 days.
Q3) A and B can do a job together in 8 days. B alone can do it in 12 days. How many days will A alone take?
A) 18 days
B) 20 days
C) 24 days
D) 32 days
Correct Option is: C) 24 days
Explanation:
Method 1: Let total work = LCM of 8 and 12 = 24 units
Together: 3 units/day
B alone: 2 units/day
A = 3 – 2 = 1 unit/day
A will take 24 / 1 = 24 days
Smart Method: A and B together complete in 8 days.
B alone completes in 12 days
LCM ( 8,12)= 24 units ( Total Work)
(A+B)’s one day’s work= 24/8 =3 units
B’s one day’s work = 24/12= 2 units.
So, A’s one day’s work= 3-2 = 1 units.( efficiency of A).
Therefore, to complete the work A alone will take = 24/1= 24 days.
Q4) A can complete a work in 15 days. After working 5 days, he is joined by B who completes the remaining work in 5 days. In how many days can B alone complete the whole work?
A) 15 days
B) 20 days
C) 25 days
D) 30 days
Correct Option is: A) 15 days
Explanation:
Method 1: A’s 5 days work = 5/15 = 1/3
Remaining = 2/3
Let B’s rate = x
A’s = 1/15
(1/15 + x) × 5 = 2/3
Multiply: 5/15 + 5x = 2/3 → 1/3 + 5x = 2/3
5x = 1/3 → x = 1/15
So, B takes 15 days to do full work.
Smart Method: A * 15= A *5 +(A+B)*5
or, 15A=10A+5B
or, 5A=5B
or, A=B
Therefore, Ratio of efficiencies of A:B = 1:1
Total Work = A*15= 1*15 = 15 units.
To complete the whole work by B alone will take = 15/1 = 15 days.
Q5) A and B together can do a work in 12 days. A alone can do it in 20 days. In how many days can B alone complete it?
A) 30 days
B) 24 days
C) 20 days
D) 15 days
Correct Option is: A) 30 days
Explanation:
Method 1: A’s 1 day = 1/20
Together = 1/12
B = 1/12 – 1/20 = (5 – 3)/60 = 2/60 = 1/30
So, B will take 30 days
Smart Method: A and B together complete in 12 days.
A alone completes in 20 days
LCM ( 12,20)= 60 units ( Total Work)
(A+B)’s one day’s work= 60/12=5 units
A’s one day’s work = 60/20= 3 units.
So, B’s one day’s work= 5-3 = 2 units.( efficiency of B).
Therefore, to complete the work B alone will take = 60/2= 30 days.
Q6) 6 men can complete a work in 12 days. How many men are needed to complete the same work in 8 days?
A) 6 men
B) 8 men
C) 9 men
D) 10 men
Correct Option is: C) 9 men
Explanation:
Work = Men × Days = 6 × 12 = 72 units
Men required = 72 / 8 = 9 men
Q7) A can complete a task in 10 days, B in 15 days. If A worked for 4 days, then left and B completed the rest, how many days did the total work take?
A) 10 days
B) 12 days
C) 11 days
D) 13 days
Correct Option is: D) 13 days
Explanation:
Method 1: A’s 4 days work = 4 × 1/10 = 0.4
Remaining = 0.6
B’s 1 day = 1/15
Time = 0.6 / (1/15) = 9 days
Total time = 4 + 9 = 13 days
Smart Method: A = 10 days, B = 15 days
LCM(10,15)= 30 units(Total Work)
A’s one day’s work= 30/10 = 3 units
B’s one day’s work = 30/ 15 = 2 units
In 4 days A completed= 4* 3= 12 units work
Remaining Work= 30-12 = 18 units.
B completed the rest work in = 18/2 =9 days.
So, total work completed in = (4+9)= 13 days.
Q8) A, B and C can complete a job in 24, 30 and 40 days respectively. Working together, how long will it take to complete the job?
A) 10 days
B) 12 days
C) 15 days
D) 16 days
Correct Option is: A) 10 days
Explanation:
Method 1: Combined work = 1/24 + 1/30 + 1/40
LCM = 120
= (5 + 4 + 3)/120 = 12/120 = 1/10
So, they can complete in 10 days
Smart Method: A, B and C can complete a job in 24, 30 and 40 days respectively
LCM( 24,30,40)= 120 units(Total Work)
A’s one day’s work= 120/24= 5 units
B’s one day’s work= 120/30= 4 units
C’s one day’s work= 120/40= 3 units
(A+B+C)’s one day’s work = 5+4+3=12 units.
So, (A+B+C) together will complete the whole work in = 120/12= 10 days.
Q9) If 8 men can do a job in 15 days, in how many days can 10 men do the same job?
A) 10 days
B) 12 days
C) 15 days
D) 18 days
Correct Option is: B) 12 days
Explanation:
Work = Men × Days = 8 × 15 = 120 units
Days = 120 / 10 = 12 days
Q10) A and B can do a job in 16 days. B and C in 20 days, and A and C in 24 days. In how many days can A alone do the work?
A) 30 days
B) 32 days
C) 37 days
D) 40 days
Correct Option is: C) 37 days
Explanation:
Method 1: A + B = 1/16, B + C = 1/20, A + C = 1/24
Add all: 2(A + B + C) = 1/16 + 1/20 + 1/24
= (15 + 12 + 10)/240 = 37/240
A + B + C = 37/480
Now A = (A + B + C) – (B + C)
= 37/480 – 1/20
= 37/480 – 24/480
= 13/480
A alone = 480/13 ≈ 37 days
Smart Method: A+B = 16 days, B+C =20 days, C+A = 24 days
LCM ( 16,20,24)= 240 units(Total Work)
(A+B)’s one day’s work= 240/16= 15 units
(B+C)’s one day’s work = 240/20= 12 units
(C+A)’s one day’s work = 240/24= 10 units
Adding all these, 2(A+B+C) = 37
Or, (A+B+C) = 37/2= 18.5 ( one day’s work)
A’s one day’s work = (A+B+C)’s one day’s work – ( B+C)’s one day’s work
= 18.5-12 = 6.5 units.
So, A alone can do the work in = 240/6.5 ≈ 37 days.
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Conclusion:-
This Time and Work Questions with Solutions PDF – Practice Set 01 is specially curated to build your basics and boost your confidence for exams. Keep practicing more sets like this to gain speed and accuracy.
Remember, in Time and Work, consistency in solving mixed types of questions helps you master the topic. Don’t forget to review concepts like efficiency, LCM method, and unit work technique.
